1. Predict
Predict separately how increasing mass and increasing spring stiffness change the period.
Dynamics
Observe the spring’s restoring force, the motion and energy conversion together. In the frictionless model, total mechanical energy is conserved.
Which energy is greatest when the mass passes through equilibrium?
Predict separately how increasing mass and increasing spring stiffness change the period.
Set m = 1 kg, k = 4 N/m, x₀ = 0.8 m, v₀ = 0. Record x, v, K, U and E at an extremum and at equilibrium during one period.
First quadruple only the mass. Restore the baseline, then quadruple only k. Measure the period ratios.
Compare with T = 2π√(m/k). Why does changing x₀ leave the period unchanged in this ideal linear model?
Use Excel data to compute time averages of K and U over one full period. Compare with E/2; distinguish instantaneous equality from equality of time averages.
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02 / LIVE MEASUREMENTS
Calculated period:
Total physical time:
One cycle is one full period: . Changing mass or stiffness changes both period and total duration. Playback speed only slows the display.
K: solid blue line; U: dashed orange line; E = K + U: dotted lavender line. Graphs are drawn up to the selected instant. E₀ − E is the energy transferred to the surroundings by the resistive force.
Where is the energy when the mass crosses equilibrium?
Start from rest and compare K, U and E at an extremum and at equilibrium.
Why does E stay constant as K and U change?
Grid spacing: 0.25 m. The position scale is fixed; equilibrium is at x = 0.
The F arrow shows the direction of the net force; its length is not a quantitative force scale.
For an ideal horizontal spring, the restoring force is Fₛ = −k x. The position x is measured relative to equilibrium. The initial conditions are x(0) = x₀ and v(0) = v₀. The natural angular frequency is ω₀ = √(k/m), and the period is T₀ = 2π/ω₀.
Dots denote derivatives with respect to time. In the expressions below, t = 0 is the selected initial instant.
K = m v²/2, U = k x²/2 and E = K + U. Since the power delivered by the resistive force is −b v², mechanical energy cannot increase. Energy is not destroyed; it is transferred from the mechanical system described by the model to the surroundings.
For stable, bound, conservative motion, an appropriate time average gives 2⟨K⟩ = ⟨x dU/dx⟩. For a harmonic potential, averaging over a full period gives ⟨K⟩ = ⟨U⟩ = E/2. This does not mean the energies are equal at every instant; we do not apply the same equality directly to damped transient motion.
One-dimensional horizontal motion, constant mass, a massless ideal Hookean spring and constant coefficients. Weight and the normal force balance vertically. There is no external driving force or measurement noise. The damped page uses only resistance proportional to velocity. Changing a parameter starts the experiment with new initial conditions; the transition during the parameter change is not modelled.
| Notation | Meaning and unit |
|---|---|
| Time; s denotes seconds. The light clock uses ns = 10⁻⁹ s. | |
| Position relative to equilibrium (m); x₀ is initial position. Its sign indicates the side of equilibrium. | |
| First time derivative of position: velocity (m/s). One dot means one derivative with respect to time. | |
| Second time derivative of position: acceleration (m/s²), the rate of change of velocity. Two dots mean two time derivatives. | |
| Mass m (kg), spring stiffness k (N/m), viscous damping coefficient b (kg/s). Drag is −bv and spring force is −kx. | |
| ω₀ is natural angular frequency (rad/s); β = b/(2m) is decay rate (s⁻¹); ζ = β/ω₀ is dimensionless damping ratio. This β is not the light clock’s v/c. | |
| Damped angular frequency (rad/s) in the underdamped regime; used as an oscillation frequency only for ζ < 1. | |
| v₀ is initial velocity (m/s). A, B and C± are solution coefficients (m) fixed by initial position and velocity, not independent parameters. | |
| Two exponential decay rates (s⁻¹) for overdamping. C₊ + C₋ = x₀ and r₊C₊ + r₋C₋ = v₀ enforce the initial conditions. | |
| K is kinetic, U is spring potential and E is total mechanical energy (J). With damping, lost mechanical energy is transferred to the environment as thermal energy. | |
| Angle brackets indicate time averages, here over a complete period or an integer number of periods of undamped periodic motion. |
The books below offer further study of the relevant concepts. The simulation’s assumptions are stated separately above.